MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Reflection of Sound Waves

When the tens...

Question

When the tension in a string is increased by $44 %$ , the frequency increases by 10 Hz. Find the frequency of the string.

Open in App

Solution

We know that, $f \propto \sqrt{T}$
Let initial tension and frequency be $T_{1}$ and $f_{1}$ respectively.
New tension, $T_{2} = T_{1} + 44 % o f T_{1} = 1.44 T_{1}$
New frequency, $f_{2} = f_{1} + 10$
Now, $\frac{f_{2}}{f_{1}} = \sqrt{\frac{T_{2}}{T_{1}}} \Rightarrow \frac{f_{1} + 10}{f_{1}} = \sqrt{\frac{1.44 T_{1}}{T_{1}}} \Rightarrow \frac{f_{1} + 10}{f_{1}} = 1.2 \Rightarrow f_{1} + 10 = 1.2 f_{1} \Rightarrow 0.2 f_{1} = 10$
$∴ f_{1} = 50 H z$

Suggest Corrections

thumbs-up

4

Similar questions

Q. When the tension in a string is increased by

44 %

, the frequency increased by

10 H z

the frequency of the string is

Q. The tension of a stretched string is increases by

44 %

. In order to keep its frequency of vibration same its length must be increased by.

Q. When tension of a string is increased by 2.5 N, the initial frequency is altered in the ratio of 3:2. The initial tension in the string is

Q. If the tension in the string is increased by

5 k g w t

the frequency of the fundamental tone increases in the ratio

2 : 3

. What was the initial tension in the string?

Q. To increase the frequency by

20 %

, the tension in the string vibrating on a Sonometer has to be increased by

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Standing Longitudinal Waves

PHYSICS

Watch in App

explore_more_icon

Explore more

Reflection of Sound Waves

Standard XII Physics

Join BYJU'S Learning Program

CrossIcon