Question

When the time is $4:20$, then the angle between the hands of the clock is

• A. ${20}^o$
• B. ${15}^o$
• C. $12{\frac{1}{2}}^o$
• D. ${10}^o$

Answer 1

The correct option is D ${10}^o$

$\theta =\frac{1}{2}(60H-11M)$

where,

$\theta$ is angle between the hour hand and minute hand.

$H$ is the no. of hours.

$M$ is in minutes.

$\therefore \theta =\frac{1}{2}(60\times 4-11\times 20)$

=$\frac{1}{2}\times 20$ = ${10}^o$