When the two identical cells are connected either in series or in parallel across a 4 ohm resistor they send the same current through it. The internal resistance of the cell is
A
1.2Ω
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B
2Ω
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C
4Ω
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D
4.8Ω
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Solution
The correct option is C4Ω In series the current through the resistor R is 2ER+2r In parallel connection, current through the resistor R is ER+r2 I=2ER+2r=ER+r22R+r=R+2rR=rr=4Ω