Question

When the velocity of a relativistic charged particle increases, it's specific charge

• A. Decreases
• B. increases
• C. Remains same
• D. First decreases then increases

Answer 1

The correct option is A Decreases

$m=\frac{m_0}{\sqrt{1-\frac{v^2}{c^2}}}$

specific charge $\frac{q}{m}=\frac{q}{m_0}\sqrt{1-\frac{v^2}{c^2}}$

so as $v$ increases the specific charge decreases