When three coins are tossed simultaneously find the probability of atmost two head
First, we make sample space for getting head or tail for 3 coins, tossed simultaneously…
Order is 1st coin, 2nd coin, 3rd coin, H for head & T for tail
HHT ……..●
HTH ……..●
HTT…….. ●
HHH
THT……….●
TTH………..●
TTT………..●
THH …….●
Here, we can see that Total no of outcomes = 8
And no of outcomes favourable to event getting at most 2 heads.= means all should not be heads ( meansHHH is exempted), means starting from no heads, gradually you can go up to 2 at the most)
So outcomes favourable to the event (getting 2 heads at most) = 8–1 = 7
Probability ( E) = (favourable outcomes)/ (total outcomes) = 7/8
ANS: 7/8