When three unbiased coins are tossed together, what is the probability of not getting two tails and one head in any order ?

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Solution

S = {HHH, HTT, THT, TTH, HHT, THH, HTH, TTT}
Event = {TTH, HTT, THT}
$P (E) = \frac{3}{8}$
$P (E) = 1 - \frac{3}{8}$
$= \frac{5}{8}$

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