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Sulphonation of Aromatics

when toluene ...

Question

when toluene reacts with Br_2/hv only one H from CH_3 group is replaced by Br , but when Cl_2/hv reacts then 2 H are replaced , pl explain the reason in detai

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Reagent used in the conversion of

(C H_{3} - C H_{3} \to C H_{3} - C H_{2} - O H) alkane \to alcohol

:

Toluene, when treated with $B r_{2} / F e$ gives p-bromotoluene as the major product because the $C H_{3}$ group:

H_{2}

gas is liberated when

H_{2} O_{2}

H_{2} S

F_{2}

the compound formed is :

B r O_{3}^{-}

ion reacts with

{B r}^{-}

in acidic medium,

{B r}_{2}

is liberated. The equivalent weight

{B r}_{2}

in this reaction is :

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Sulphonation of Aromatics

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