When two dice are rolled, find the probability of getting a greater number on the first die than the one on the second, given that the sum should equal 8.
There are 5 ways to get a sum of 8 when two dice are rolled ={(2,6),(3,5),(4,4),(5,3),(6,2)}
And there are two ways where the number on the first die is greater than the one on the second given that the sum should equal 8, G={(5,3),(6,2)}
Therefore, P(Sum equals 8) =536 and P(G) =236
Now, P(G | Sum equals 8) =P(Gandsumequals8)P(sumequals8)
=(2/36)(5/36) =25