Question

When two dice are thrown at the same time, what is the probability that one dice shows up $3$ and the other does not show up $3$?

• A. $\frac{1}{18}$
• B. $\frac{5}{36}$
• C. $\frac{1}{36}$
• D. $\frac{1}{6}$

Answer 1

Answer: (B)

$\frac{5}{36}$

Total no. of out comes when two dice are thrown, n(S)=$6\times 6=36$

The favorable outcome $=(3,1),(3,2),(3,4),(3,5),(3,6)$

$\Rightarrow$Total no.of favorable outcomes,n(E)=5

$\therefore Probability\left(P\right)=\frac{n\left(E\right)}{n\left(S\right)}=\frac{5}{36}$