Question

When two dice are thrown simultaneously the probability that the sum of the two numbers that turn up is more than $11$ is:

• A. $\frac{11}{12}$
• B. $\frac{1}{36}$
• C. $\frac{2}{12}$
• D. $\frac{1}{8}$

Answer 1

The correct option is B $\frac{1}{36}$

Given: two dice are thrown

To find the probability that the sum of the two numbers that turn up is more than $11$

According to the question $n\left(S\right)=6\times 6=36$

Favorable outcomes for sum more than $11$ is $\left\{\right(6,6\left)\right\}$

$\Rightarrow n\left(E\right)=1$

Hence, the probability of getting a total more than $11$ is $\frac{n\left(E\right)}{n\left(S\right)}=\frac{1}{36}$