When two dice are thrown simultaneously, what is the probability that the sum of the two numbers that turn up is less or equal to 10?
First find the probability of sum being greater than 10. Combination whose sum of 12 is (6, 6)
Combinations whose sum of 11 is (5, 6), (6, 5).
Therefore, there are totally 3 occurrences out of 36 occurrences that go against the given condition.
Probability whose sum of two numbers is greater than or equal to 11 = 336 = 112.
Hence probability whose sum of two numbers is lesser than 11 = 1 – 112= 1112 .