When two dice are thrown, the probability of getting a number always greater than $4$ on the second dice is ____________.

\frac{1}{6}

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\frac{1}{3}

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\frac{1}{36}

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\frac{5}{36}

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Solution

The correct option is B $\frac{1}{3}$
Possible outcomes on rolling two dices are $36$
Out of the possible outcomes, chances of getting a number greater than $4$ on second dice are $2 \times 6$ because on second dice, number should be either $5$ or $6$ but first dice can have any of the $6$ numbers.

Probability $=$ Favourable Outcomes $\div$ Total Outcomes $= \frac{12}{36} = \frac{1}{3}$

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When two dice are thrown, the probability of getting a number always greater than 4 on the second dice is ____________.

When two dice are thrown, the probability of getting a number always greater than $4$ on the second dice is ____________.