When two equal forces are inclined at an angle 2α, their resultant is twice as great as when they act at an angle 2β, then
A
cosα=2cosβ
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B
cosα=2sinβ
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C
cosβ=2cosα
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D
sinβ=2cosα
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Solution
The correct option is Acosα=2cosβ Let the magnitude of each force be P. Then, R1= Resultant of two equal forces each of magnitude P inclined at an angle 2α=2Pcosα, and R2 = Resultant of two equal forces each of magnitude P inclined at an angle 2β=2Pcosβ. It is given that, R1=2R2 ⇒2Pcosα=4Pcosβ ⇒cosα=2cosβ