Question

When two isomeric aromatic liquid compounds A and B having hydrogen bond, are heated. Compound A boils at a lower temperature than B.

Which statement is correct?

• A. Intermolecular H bonding present in A
• B. Intramolecular H bonding present in A and B both
• C. Intramolecular H bonding present in B
• D. Intramolecular H bonding present in A

Answer 1

Answer: (A), (B), (C), (D)

The correct options are
A Intermolecular H bonding present in A
B Intramolecular H bonding present in A and B both
C Intramolecular H bonding present in B
D Intramolecular H bonding present in A

Since the compounds are aromatic and isomeric therefore the structural difference lies only in the arrangement of substituents on the ring.

So, there lies the possibility of being intermolecular in B and intramolecular in A.There lies possibility of intramolecular in both or intermolecular in both.

Therefore option (A),(B),(C),(D) all can be correct.