Question

When two isomeric liquid compounds ${}^{\prime }{A}^{\prime }$ and ${}^{\prime }{B}^{\prime }$ form $H-$bonding are heated, compound ${}^{\prime }{A}^{\prime }$ boils at lower temperature than ${}^{\prime }{B}^{\prime }$. Which of the following is correct for ${}^{\prime }{A}^{\prime }$ and ${}^{\prime }{B}^{\prime }$?

• A. Intermolecular $H-$bonding present in ${}^{\prime }{A}^{\prime }$
• B. Intramolecular $H-$bonding present in ${}^{\prime }{A}^{\prime }$
• C. Intramolecular $H-$bonding present in ${}^{\prime }{B}^{\prime }$
• D. None of the above

Answer 1

The correct option is B Intramolecular $H-$bonding present in ${}^{\prime }{A}^{\prime }$

Correct Option $-C$

Reason:- $B$ takes a higher temperature to boil than $A$. This implies some type of intramolecular hydrogen bonding is present in $B$ which takes more amount of energy to break.