When two lines of slopes $m_{1} & m_{2}$ are perpendicular to each other. Product of their slopes is 1

True

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False

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Solution

The correct option is B
False

When two lines are perpendicular.
Tangent of angle between them is NOT defined.
$t a n θ = | \frac{m_{1} - m_{2}}{1 + m_{1} . m_{2}} |$
For perpendicular lines
$1 + m_{1} . m_{2} = 0$
$m_{1} . m_{2} = - 1$
Product of their slopes should be -1

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Similar questions

Q. If two lines are perpendicular with respect to each other, then the product of their slopes is equal to .

Q. If two lines having slopes

m_{1}

and

m_{2}

are parallel to each other, then which of the following is correct?

Statement 1 : If two lines are perpendicular, then product of their slopes is –1.
Statement 2: If the product of slopes of two lines is –1, then these lines will be perpendicular.

Q. If two lines having slopes

m_{1}

and

m_{2}

are parallel to each other, then which of the following is correct?

m₁ and m₂ are the slope of two perpendicular lines, if

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When two lines of slopes m1 & m2 are perpendicular to each other. Product of their slopes is 1

The correct option is B False When two lines are perpendicular. Tangent of angle between them is NOT defined. tanθ=|m1−m21+m1.m2| For perpendicular lines 1+m1.m2=0 m1.m2=−1 Product of their slopes should be -1

When two lines of slopes $m_{1} & m_{2}$ are perpendicular to each other. Product of their slopes is 1

The correct option is B
False

When two lines are perpendicular.
Tangent of angle between them is NOT defined.
$t a n θ = | \frac{m_{1} - m_{2}}{1 + m_{1} . m_{2}} |$
For perpendicular lines
$1 + m_{1} . m_{2} = 0$
$m_{1} . m_{2} = - 1$
Product of their slopes should be -1