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Equipartition Theorem

When two mole...

Question

When two mole of an ideal $(C_{p . m} = \frac{5}{2} R)$ heated from 300 K to 600 K at constant pressure. The change in entropy of gas $Δ S$ is

\frac{3}{2} R l n 2

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- \frac{3}{2} R l n 2

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5 R l n 2

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\frac{5}{2} R l n 2

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Solution

The correct option is C $5 R l n 2$
$Δ S = n C p . m I n \frac{T_{2}}{T_{1}} = 2 \times \frac{5}{2} R l n \frac{600}{300} = 5 R l n 2$

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