When two tuning forks A and B are sounded together, the number of beats heard is ν. The frequency of fork A is f. If the prong of fork B is loaded with a little wax, the number of beats decreases. The initial frequency of fork B is
A
f+ν
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B
f−ν
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C
f+2ν
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D
f−2ν
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Solution
The correct option is Af+ν Let f0 be the initial frequency of fork B.
Number of beats heard per second is ν, when fork A and B are sounded together. ⇒fb=|fA−f0|=ν ⇒f0=f+ν or f−ν
When fork B is loaded with wax, its frequency decreases. However, it is given that beat frequency also decreases. ⇒ Frequency of tuning fork B is higher than A. ∴(a) is the correct answer.