Question

When two tuning forks $A$ and $B$ are sounded together, $x$ beats $s^{-1}$ are heard. Frequency of $A$ is $n$. Now when one prong of $B$ is loaded with a little wax, the number of beats per second decrease. The frequency of fork $B$ is

• A. $n+x$
• B. $n-x$
• C. $n-x^2$
• D. $n-2x$

Answer 1

The correct option is A $n+x$

$|{\nu }_a-{\nu }_b|=x$

Since putting wax reduces the frequency of the tuning fork, ${\nu }_b$ is

greater than ${\nu }_a$
Thus ${\nu }_b=n+x$