When u238 nucleus, originally at rest, decays by emitting an alpha particle having a speed u, the recoil speed of the residual nucleus is
A
4u238
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B
−4u234
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C
4u234
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D
−4u238
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Solution
The correct option is C4u234 mass of α - particle, m_1=4 amu Mass of residual nucleus, m2 = 238-4=234 amu By conservation of momentum m1u+m2v=0 V=−4u234