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Standard XII

Chemistry

Kinetic Theory of Gases

When ultravio...

Question

When ultraviolet light is incident on a photocell, its stopping potential is $V_{0}$ and the maximum kinetic energy of the photoelectrons is $K_{m a x}$ . When X- rays are incident on the same cell

V_{0} and K_{m a x}

both increases

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V_{0} and K_{m a x}

both decreases

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V_{0} increases but K_{m a x}

remains the same

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K_{m a x} increases but V_{0}

remains the same

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Solution

The correct option is A $V_{0} and K_{m a x}$ both increases
For $X$ -rays $E ↑↑$ (very high) incomparision with Ultraviolet rays.

Using $K_{m a x} = E - ϕ$

As $E$ is increasing, $K_{m a x}$ increases.

we know that $K_{m a x} = e V_{0}$
Hence stopping potential $(V_{0})$ increases.

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Similar questions

Q. Assertion :When ultraviolet light is incident on a photocell, its stopping potential is

V_{0}

and the maximum kinetic energy of the photoelectrons is

K_{m a x}

. When the ultraviolet light is replaced by X-rays, both

V_{0}

and

K_{m a x}

increase. Reason: Photoelectrons are emitted with speeds ranging from zero to a maximum value because of the range of frequencies present in the incident light.

Q. Statement-l : When ultraviolet light is incident on a photocell, its stopping potential is

V_{0}

and the maximum kinetic energy of the photoelectrons is

K_{max}

. When the ultraviolet light is replaced by X- rays, both

V_{0}

and

K_{max}

increase.
Statement-2 : Photoelectrons are emitted with speeds ranging from zero to a maximum value because of the range of frequencies present in the incident light.

Q. Statement-1 : When ultraviolet light is incident on a photocell, its stopping potential is

v_{0}

and the maximum kinetic energy of the photo electrons is

K_{m a x}

. When the ultraviolet light is replaced by X-rays,

K_{m a x}

increases but

v_{0}

, decreases.
Statement -2: Photo electrons are emitted with speeds ranging from zero to a maximum value.Below a certain negative voltage

V_{0}

,no photons are emitted in a photocell

Q. Statement -1 :When ultraviolet light is incident on a photo cell, its potential is

V_{0}

and the maximum kinetic energy of the photoelectrons is

K_{m a x}

. When the ultravoilet light is replaced by X-rays, both

V_{0}

and

K_{m a x}

increase.

Statement-2: Photoelctrons are emitted with speeds ranging from zero to a maximum value because of the range of frequencies present in the incident light.

Q. Statement - 1: When ultraviolet light is incident on a photocell, its stopping potential is

V_{0}

and the maximum kinetic energy of the photoelectrons is

K_{m a x}

. When the ultraviolet light is replaced by X - rays, both

V_{0} a n d K_{m a x}

increase.
Statement - 2: Photoelectrons are emitted with speeds ranging from zero to a maximum value because of the range of frequencies present in the incident light.

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When ultraviolet light is incident on a photocell, its stopping potential is V0 and the maximum kinetic energy of the photoelectrons is Kmax. When X- rays are incident on the same cell

The correct option is A V0 and Kmax both increasesFor X -rays E ↑↑ (very high) incomparision with Ultraviolet rays. Using Kmax=E−ϕ As E is increasing, Kmax increases. we know that Kmax=eV0 Hence stopping potential(V0) increases.

When ultraviolet light is incident on a photocell, its stopping potential is $V_{0}$ and the maximum kinetic energy of the photoelectrons is $K_{m a x}$ . When X- rays are incident on the same cell

The correct option is A $V_{0} and K_{m a x}$ both increases
For $X$ -rays $E ↑↑$ (very high) incomparision with Ultraviolet rays.

Using $K_{m a x} = E - ϕ$

As $E$ is increasing, $K_{m a x}$ increases.

we know that $K_{m a x} = e V_{0}$
Hence stopping potential $(V_{0})$ increases.