Question

When ultraviolet radiation is incident on a surface, no photoelectrons are emitted. If another beam causes photoelectrons to be emitted from the same surface in a separate case, then it may consist of
$\left(a\right)$ Radio waves
$\left(b\right)$ Infrared rays
$\left(c\right)$ X-rays
$\left(d\right)$ Gamma rays

• A. $\left(a\right)$ and $\left(b\right)$
• B. $\left(b\right)$ and $\left(c\right)$
• C. $\left(a\right)$ and $\left(d\right)$
• D. $\left(c\right)$ and $\left(d\right)$

Answer 1

The correct option is D $\left(c\right)$ and $\left(d\right)$

Frequencies are related as follows,
${\nu }_{gamma}>{\nu }_{X-rays}>{\nu }_{ultraviolet}$

Hence, X-rays and gamma rays can give photoelectrons from the same surface.