Question

When using cross multiplication for solving

$a_{1}x$ + $b_{1}y$ + $c_1$ = 0

$a_{2}x$ + $b_{2}y$ + $c_2$ = 0

y = $\frac{c_1{a}_2-c_2{a}_1}{a_1{b}_2-a_2{b}_1}$

• A. True
• B. False

Answer 1

The correct option is A

True

Let

$a_{1}x$ + $b_{1}y$ + $c_1$ = 0 ......(1)

$a_{2}x$ + $b_{2}y$ + $c_2$ = 0 ......(2)

In the process of cross multiplication method to solve for 'y',
we multiply Eq(1) with $a_2$ and Eq(2) with $a_1$
and solving for y,
we get,



$\Rightarrow y=\frac{c_1{a}_2-c_2{a}_1}{a_1{b}_2-a_2{b}_1}$

Hence the given statement is true.