When using cross multiplication for solving
a1x + b1y + c1 = 0
a2x + b2y + c2 = 0
x=b1c2−b2c1a1b2−a2b1
True
Given,
a1x + b1y + c1 = 0 ......(1)
a2x + b2y + c2 = 0 ......(2)
In the process of cross multiplication method to solve for 'x',
we multiply Eq(1) with b2 and Eq(2) with b1
and solving for x,
we get,
⇒x=b1c2−b2c1a1b2−a2b1.
Hence the given statement is true.