Question

When two waves of almost equal frequencies $v_1$ and $v_2$ reach a point simultaneously, the time interval between successive maxima is

• A. $v_1-v_2$
• B. $v_1+v_2$
• C. $\raisebox{1ex}{$1$}\!\left/ \!\raisebox{-1ex}{$v_1+v_2$}\right.$
• D. $\raisebox{1ex}{$1$}\!\left/ \!\raisebox{-1ex}{$v_1-v_2$}\right.$

Answer 1

The correct option is D

$\raisebox{1ex}{$1$}\!\left/ \!\raisebox{-1ex}{$v_1-v_2$}\right.$

Explanation for correct option:-

1. When two waves of almost equal frequencies $v_1$ and $v_2$ reach a point simultaneously, the beat frequency is given by, $\nu b={\nu }_2-{\nu }_1$ where ${\nu }_2-{\nu }_1$is the difference between the two frequencies.
2. The relationship between time and frequency is, $T=\frac{1}{f}$ where $T$ is time and $f$ is the frequency so the equation for the time interval is $1/(v_1-v_2)$

Hence, option (D) is the right answer.