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Standard XII

Physics

Bernoulli's Principle

When water is...

Question

When water is flowing through a pipe with a speed $v$ , then its power is proportional to

v^{2}

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v^{3 / 2}

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v^{3}

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\sqrt{v}

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Solution

The correct option is A $v^{2}$

Using Bernoulli's equation.
Energy per unit volume before $=$ Energy per unit volume after
$p_{1} + \frac{1}{2} {p v}_{1}^{2} + {p g h}_{1} = p_{2} + \frac{1}{2} {p v}_{2}^{2} + {p g h}_{2}$
$A_{2} < A_{1}$
$V_{2} > V_{1}$
$p_{2} < p_{1}$
Hence power $α v^{2}$ .

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When water is flowing through a pipe with a speed v, then its power is proportional to

The correct option is A v2Using Bernoulli's equation.Energy per unit volume before = Energy per unit volume afterp1+12pv21+pgh1=p2+12pv22+pgh2A2<A1V2>V1p2<p1Hence power αv2.

When water is flowing through a pipe with a speed $v$ , then its power is proportional to

The correct option is A $v^{2}$

Using Bernoulli's equation.
Energy per unit volume before $=$ Energy per unit volume after
$p_{1} + \frac{1}{2} {p v}_{1}^{2} + {p g h}_{1} = p_{2} + \frac{1}{2} {p v}_{2}^{2} + {p g h}_{2}$
$A_{2} < A_{1}$
$V_{2} > V_{1}$
$p_{2} < p_{1}$
Hence power $α v^{2}$ .