When water is heated from 0 - C to 4 - C - then

The correct option is C C _ p Water has highest density at 4^o C #160;This changes its properties from other simple fluids.When water is heated from 0 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Density

When water is...

Question

When water is heated from 0 $^{\circ} C$ to 4 $^{\circ} C$ , then

C_{p} = C_{v}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C_{p} > C_{v}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C_{p} < C_{v}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

C_{p} - C_{v} = R

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $C_{p} < C_{v}$
Water has highest density at $4^{o} C$ This changes its properties from other simple fluids.
When water is heated from $0^{o} C$ to $4^{o} C$ , the volume of liquid decreases.
Thus for this transition, PΔV is negative.
So we can write:

$\int C_{p} d T = \int C_{v} d T + P Δ V$

$⟹ C_{p} < C_{v}$

Hence option C is correct

Suggest Corrections

Similar questions

Q. If

C_{P}

and

C_{V}

denote the specific heats of nitrogen per unit mass at constant pressure and constant volume respectively, then

Q. If

C_{p}

and

C_{V}

denotes the specific heats of unit mass nitrogen at constant pressure and volume respectively, then

Q. When water is heated from

0^{\circ} C

4^{\circ} C

and

C_{p}

and

C_{v}

are its specific heated at constant pressure and constant volume respectively, then:

An ideal gas undergoes a quasi static, reversible process in which its molar heat capacity C remains constant. If during this process the relation of pressure P and volume V is given by $P V^{n}$ = constant, then n is given by (Here $C_{P}$ and $C_{V}$ are molar specific heat at constant pressure and constant volume, respectively):

Q. The ratio of two specific heats

\frac{C_{P}}{C_{V}}

of CO is

Join BYJU'S Learning Program

When water is heated from 0 ∘C to 4 ∘C , then

The correct option is C Cp<CvWater has highest density at 4oC This changes its properties from other simple fluids.When water is heated from 0oC to 4oC, the volume of liquid decreases.Thus for this transition, PΔV is negative.So we can write:∫CpdT=∫CvdT+PΔV⟹Cp<CvHence option C is correct

When water is heated from 0 $^{\circ} C$ to 4 $^{\circ} C$ , then