When we add $5 a^{2} b + 6 a b + 7 b c + 54$ and $14 a b + 8 b c + 16$ , we get:

$5 a^{2} b + 20 a b + 7 b c + 70$

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$5 a^{2} b + 6 a b + 7 b c + 8 a c + 70$

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$5 a^{2} b + 16 a b + 7 b c + 8 a c + 70$

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$5 a^{2} b + 20 a b + 15 b c + 70$

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Solution

The correct option is D
$5 a^{2} b + 20 a b + 15 b c + 70$

$5 a^{2} b + 6 a b + 7 b c + 54$
$14 a b + 8 b c + 16$
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$5 a^{2} b + 20 a b + 15 b c + 70$

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Similar questions

When we add $5 a^{2} b + 6 a b + 7 b c + 54$ to $14 a b + 8 b c + 16$ , we will get:

Adding $5 a^{2} b$ + 6ab + 7bc + 54 with 14ab + 8ac + 16, we get:

\frac{1}{3}

\frac{1}{3}

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