Question

When we add $5a^{2}b+6ab+7bc+54$ to $14ab+8ac+16$, we will get:

• A. b + 20ab + 7bc + 70
  
  
• B. b + 6ab + 7bc + 8ac + 70
  
  
• C. b + 16ab + 7bc + 8ac + 70
  
  
• D. b + 20ab + 7bc + 8ac + 70
  
  

Answer 1

The correct option is D

b + 20ab + 7bc + 8ac + 70

$5a^{2}b+6ab+7bc+54$
$\underset{–}{14ab+16+8ac}$
$5a^{2}b+20ab+7bc+70+8ac$

This cannot be simplified further as $5a^{2}b,20ab,7bc,70$ and $8ac$ are unlike terms.