For the decomposition reaction $4 H N O_{3} (g) ⇌ 4 N O_{2} (g) + 2 H_{2} O + O_{2}$ (g) if we start with only the reactant $H N O_{3}$ and p = equilibrium pressure, the equilibrium constant $K_{p}$ is:

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When we clap our hands, the sound produced is best described by Hence p denotes the change in pressure from the equilibrium value.

The correct option is D p=∑ponsin(knx−ωnt)p=∑ponsin(knx−wnt)Whenever we clap, because of disturbance wave is formed. everytime the variation won't be uniform, therefore we have to sum up all the values.

When we clap our hands, the sound produced is best described by Hence $p$ denotes the change in pressure from the equilibrium value.

The correct option is D $p = \sum p_{o n} sin (k_{n} x - ω_{n} t)$
$p = \sum p_{o n} sin (k_{n} x - w_{n} t)$
Whenever we clap, because of disturbance wave is formed. everytime the variation won't be uniform, therefore we have to sum up all the values.