When we divide $3 t^{4} + 5 t^{3} - 7 t^{2} + 2 t + 2$ by $t^{2} + 3 t + 1$ , we get $3 t^{2} - 4 t + 2$ as quotient.

True

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

False

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A
True

Lets divide $3 t^{4} + 5 t^{3} - 7 t^{2} + 2 t + 2 by t^{2} + 3 t + 1$ ,

$3 t^{2} - 4 t + 2 t^{2} + 3 t + 1) ¯ ¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯ ¯ 3 t^{4} + 5 t^{3} - 7 t^{2} + 2 t + 2_{-} 3 t^{4} \pm 9 t^{3} \pm 3 t^{2} - --------------- - - 4 t^{3} - 10 t^{2} + 2 t \mp 4 t^{3} \mp 12 t^{2} \mp 4 t - ----------------- - 2 t^{2} + 6 t + 2_{-} 2 t^{2} \pm 6 t \pm 2 - ------------ - 00$

Thus, the given statement is true.

Suggest Corrections

Similar questions

When we divide $3 t^{4} + 5 t^{3} - 7 t^{2} + 2 t + 2$ by $t^{2} + 3 t + 1$ , we get $3 t^{2} - 4 t + 2$ .

If we rotate $y^{2} = 4 a x$ by $90^{\circ}$ clockwise, we get $x^{2} = 4 a y$ .

x^{2} + 2 x + 9

x + 1

x^{2} + 2 x + 9

x + 1

a = 4 t + 3

(m / s^{2})

t

t = 0, u = 3 m / s, x = 0 m

Join BYJU'S Learning Program