When we divide $x^{2} + 2 x + 9$ by $x + 1$ we get a remainder of .

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Solution

The correct option is C 8
According to the remainder theorem, the remainder obtained when a polynomial P( $x$ ) is divided by ( $x - a$ ) is P(a).
Given, P( $x$ ) = $x^{2} + 2 x + 9$ .
Comparing ( $x - a)$ with ( $x + 1)$ , we get a = -1.
Hence, P(-1) = $(- 1)^{2} + 2 \times (- 1) + 9$ = 8.
So, the remainder = 8.

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