When we factorise y2+xy+yz+xz, one of the factor is _____________
(x2+2x+3)
Given that
y2+xy+yz+xz = y(y+x)+z(y+x)
( taking y common from the first two terms and z common from the last two terms )
= (y+z)(y+x)
Hence y2+xy+yz+xz = (y+z)(y+x)