Question

When we factorise $y^2+xy+yz+xz$, one of the factors is _____________

• A. 1/2(x²+2x+3)
• B. 1/2
• C. (x²+2x+3)
• D. 1

Answer 1

The correct option is C

(x²+2x+3)

Given that $y^2+xy+yz+xz$ = $y(y+x)+z(y+x)$ ( taking $yx$ common from the first two terms and $z$ common from the last two terms )

= $(y+z)(y+x)$ ( Taking the common bracket )

Hence $y^2+xy+yz+xz$ = $(y+z)(y+x)$