When we have to make compounds for a given formula. How will we know where do we have to put a single/double or triple bond?

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Solution

$I f t h e g i v e n c o m p o u n d s a t i s f i e s t h e f o r m u l a C_{n} H_{2 n + 2}, i t r e p r e s e n t s t h e a l k a n e s a n d a l k a n e s a r e h a v i n g \sin g l e b o n d o n l y . F o r e x ., C_{2} H_{6} - h a s t h e s t r u c t u r e o f C H_{3} - C H_{3} . I f t h e g i v e n c o m p o u n d s a t i s f i e s t h e f o r m u l a C_{n} H_{2 n}, i t r e p r e s e n t s t h e a l k e n e s a n d a l k e n e s a r e h a v i n g d o u b l e b o n d . F o r e x ., C_{2} H_{4} - h a s t h e s t r u c t u r e o f C H_{2} = C H_{2} I f t h e g i v e n c o m p o u n d s a t i s f i e s t h e f o r m u l a C_{n} H_{2 n - 2}, i t r e p r e s e n t s t h e a l k y n e s a n d a l k y n e s a r e h a v i n g t r i p l e b o n d . F o r e x ., C_{2} H_{2} - h a s t h e s t r u c t u r e o f C H \equiv C H$

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