Question

When white ppt. of $A{g}_{2}C{O}_3$ is dissolved in $N{H}_3$ solution, then compound '$X$' is formed. How many d-orbitals are involved in hybridization of '$X$'?

• A. 0
• B. 2
• C. 1
• D. 3

Answer 1

The correct option is A 0

$A{g}_{2}C{O}_3+4N{H}_3⟶2\left[Ag\right(NH{)}_3{]}^{+}+C{O}_3^{2-}$

From the above reaction, $X=\left[Ag\right(N{H}_3{)}_2{]}^{+}$

Here hybridisation of $Ag$ is $sp$ (linear). So, no ${}^{\prime }{d}^{\prime }$ orbital is involved.