When x3−2x2+ax−b is divided x2−2x−3, the remainder is x-6. The values o a and b are respectively
A
-2, -6
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B
2 and -6
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C
-2 and 6
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D
2 and 6
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Solution
The correct option is C -2 and 6 x2−2x−3)x3−2x2+ax−b(xx3−2x2−3x(a+3)x−b Remainder =(a+3)x-b=x-6 (given) equality coeffication of x & constant a+3=1 & b=6 a=-2 & b=6