Question

When $x=3$ and $y=5$, by how much does the value of $3x^2-2y$ exceed the value of $2x^2-3y$?

• A. $4$
• B. $14$
• C. $19$
• D. $20$
• E. $50$

Answer 1

Answer: (B)

$14$

Given, $x=3,y=5$

Then value of $3x^2-2y=3\times (3{)}^2-2\times 5$

$\Rightarrow 3\times 9-10$

$\Rightarrow 27-10=17$

Value of $2x^2-3y=2\times (3{)}^2-3\times 5$

$\Rightarrow 2\times 9-15$

$\Rightarrow 18-15=3$

The value of $3x^2-2y$ exceed the value of $2x^2-3y$ by $17-3=14$.