When $x = 4$ and $y = 2$ , find the value of :
$x^{2} - 2 x y + y^{2}$

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Solution

We have $x^{2} - 2 x y + y^{2}$
Substituting $x = 4$ and $y = 2$ in the expression we get
$x^{2} - 2 x y + y^{2} = 4^{2} - 2 \times 4 \times 2 + 2^{2} = 16 - 16 + 4 = 4$
Hence, the value of $x^{2} - 2 x y + y^{2}$ is $4$ .

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