When x grams of steam is mixed with y grams of ice at 0- C- we obtain x - y grams of water at 100- C- The ratio y - x is-A- 1B- 2C- 3D- 4

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Standard XII

Physics

Specific Heat Capacity

When x grams ...

Question

When x grams of steam is mixed with y grams of ice at $0^{\circ} C$ , we obtain $(x + y)$ grams of water at $100^{\circ} C$ . The ratio $\frac{y}{x}$ is:

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Solution

The correct option is C 3
Using the principle of calorimetry,
Heat lost = heat gained
$x \times 540 = y \times 80 + y \times 100.$
Hence, $\frac{y}{x} = 3$

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When x grams of steam is mixed with y grams of ice at 0∘C, we obtain (x+y) grams of water at 100∘C. The ratio yx is:

The correct option is C 3Using the principle of calorimetry, Heat lost = heat gained x×540=y×80+y×100. Hence, yx=3

When x grams of steam is mixed with y grams of ice at $0^{\circ} C$ , we obtain $(x + y)$ grams of water at $100^{\circ} C$ . The ratio $\frac{y}{x}$ is:

The correct option is C 3
Using the principle of calorimetry,
Heat lost = heat gained
$x \times 540 = y \times 80 + y \times 100.$
Hence, $\frac{y}{x} = 3$