Question

When x is divided by 6, remainder obtained is 3. Find the remainder when $x^4+x^3+x^2+x+1$ is divided by 6.

• A. 3
• B. 4
• C. 1
• D. 5

Answer 1

The correct option is C 1

$\frac{x^4+x^3+x^2+x+1}{6}=\frac{(3{)}^4+(3{)}^3+(3{)}^2+(3)+1}{6}[since\frac{x}{6}=\frac{3}{6}]=\frac{121}{6}$ = (Remainder obtained is 1)