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Question

When x3 + ax2 + 4x - 5 is divided by x + 1, the remainder is 14. Find a.

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Solution

Let px=x3+ax2+4x-5Here, divisor=x+1 When x+1=0, we have x=-1Putting x=-1 in px, we get:Remainder =p-1=-13+a-12+4-1-5 =-1+a-4-5 =a-10Given: Remainder=14i.e., a-10=14a=14+10a=24

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