When $X e F_{4}$ is treated with water, which of the following compounds is not formed ?

X e O_{2}

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X e O_{3}

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H F

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O_{2}

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Solution

The correct option is A $X e O_{2}$
The given reaction is
$6 X e F_{4} + 12 H_{2} O \to 4 X e + 2 X e O_{3} + 24 H F + 3 O_{2}$
So $X e O_{2}$ is not formed in the reaction.

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