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Standard XII

Chemistry

Potassium Permanganate

When XO2 is...

Question

When ${X O}_{2}$ is fused with an alkali metal hydroxide in presence of an oxidizing agent such as $K {N O}_{3}$ ; a dark green product is formed which disproportionates in acidic solution to afford a dark purple solution. $X$ is:

C r

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V

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T i

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M n

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Solution

The correct option is D $M n$
When fused with alkali metal hydroxide in presence of oxidising agent

$M n O_{2} + 2 K O H + K N O_{3} \to K_{2} M n O_{4} + K N O_{2} + H_{2} O$
(green)

Disproportionation reaction is as following:

$M n O_{4}^{-} 2 + 4 H^{+} \to 2 M n O_{4}^{-} + M n O_{2} + 2 H_{2} O$
(purple)

Hence, the correct option is $D$ .

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Similar questions

Q. When

M n O_{2}

is fused with

K O H

in the presence of

K N O_{3}

as an oxidizing agent, it gives a dark green compound (A).
Compound (A) disproportionates in acidic solution to give purple compound (B).
An alkaline solution of compound (B) oxidises

K I

to compound (C) whereas an acidified solution of compound (B) oxidises

K I

to (D). Identify (A), (B), (C), and (D).

Q. Choose the correct answer from the alternative given.
When an oxide of manganese (P) is fused with KOH in the presence of an oxidizing agent and dissolved in water, it gives a dark green solution of compound (Q). Compound (Q) disproportionates in neutral or acidic solution to give purple compound (R). An alkaline solution of compound (R) oxidizes potassium iodide solution to a compound (S) and compound (P) is also formed. Compounds P to S are:

M n O_{2}

when fused with KOH and oxidized in air gives a dark green compound X. In acidic X. In acidic solution, X undergoes disproportion to give an intense purple compound Y and

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$M n O_{2}$ when fused with KOH and oxidized in air gives a dark green compound X. In acidic X. In acidic solution, X undergoes disproportion to give an intense purple compound Y and $M n O_{2}$ . The compounds X and Y respectively, are

Q. Pyrolusite on heating with

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When XO2 is fused with an alkali metal hydroxide in presence of an oxidizing agent such as KNO3; a dark green product is formed which disproportionates in acidic solution to afford a dark purple solution. X is:

The correct option is D MnWhen fused with alkali metal hydroxide in presence of oxidising agentMnO2+2KOH+KNO3→K2MnO4+KNO2+H2O (green)Disproportionation reaction is as following:MnO−42+4H+→2MnO−4+MnO2+2H2O (purple)Hence, the correct option is D.

When ${X O}_{2}$ is fused with an alkali metal hydroxide in presence of an oxidizing agent such as $K {N O}_{3}$ ; a dark green product is formed which disproportionates in acidic solution to afford a dark purple solution. $X$ is: