When ${X O}_{2}$ is fused with an alkali metal hydroxide in presence of an oxidizing agent such as $K {N O}_{3}$ ; a dark green product is formed which disproportionates in acidic solution to afford a dark purple solution. $X$ is:

C r

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V

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T i

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M n

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Solution

The correct option is D $M n$
When fused with alkali metal hydroxide in presence of oxidising agent

$M n O_{2} + 2 K O H + K N O_{3} \to K_{2} M n O_{4} + K N O_{2} + H_{2} O$
(green)

Disproportionation reaction is as following:

$M n O_{4}^{-} 2 + 4 H^{+} \to 2 M n O_{4}^{-} + M n O_{2} + 2 H_{2} O$
(purple)

Hence, the correct option is $D$ .

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Similar questions

Q. When

M n O_{2}

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K O H

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K N O_{3}

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An alkaline solution of compound (B) oxidises

K I

to compound (C) whereas an acidified solution of compound (B) oxidises

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Q. Choose the correct answer from the alternative given.
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When XO2 is fused with an alkali metal hydroxide in presence of an oxidizing agent such as KNO3; a dark green product is formed which disproportionates in acidic solution to afford a dark purple solution. X is:

The correct option is D MnWhen fused with alkali metal hydroxide in presence of oxidising agentMnO2+2KOH+KNO3→K2MnO4+KNO2+H2O (green)Disproportionation reaction is as following:MnO−42+4H+→2MnO−4+MnO2+2H2O (purple)Hence, the correct option is D.

When ${X O}_{2}$ is fused with an alkali metal hydroxide in presence of an oxidizing agent such as $K {N O}_{3}$ ; a dark green product is formed which disproportionates in acidic solution to afford a dark purple solution. $X$ is: