Question

When you add a two - digit number and the number obtained by reversing the order of it's digits, the sum is 165. If the digits of the number differ by three find the number.

Answer 1

Let no at ones= x
Let no. at tens=10(x+3)
=10x+ 30
so the number is 10x+30+x

New no.reversing the order of the digit
Let no. at ones place x+3
let no. at tens place 10x
So the reversed number is 10x+x+3

Sum of these numbers is 165

• (10x +30+x )+ (10x + x +3)= 165

22x=132
x = 132/22
=6

The original no. is 69
The new no. is 96.