When zinc is added to $C u S O_{4}$ solution, copper is precipitated because :

C u^{+ 2}

is reduced

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C u^{+ 2}

is oxidised

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C u S O_{4}

is ionized

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C u S O_{4}

is hydrolysed

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Solution

The correct option is A $C u^{+ 2}$ is reduced
Zinc is placed above copper in reactivity series. Thus, it can displace copper from its solution.
Thus, $Z n$ being a more reactive element and displaces $C u$ to form a solution of zinc sulphate.
$Z n + C u S O_{4} \to Z n S O_{4} + C u$

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C u S O_{4}

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0.05 M

C u {S O}_{4}

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Identify the oxidising and reducing agents in the reaction:

Zn + CuSO₄ → Cu + ZnSO₄

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