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Valency and Oxidation State

When zinc rea...

Question

When zinc reacts with very dilute $H N O_{3}$ , the oxidation state of nitrogen changes from:

+ 5

+ 1

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+ 5

- 3

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+ 5

+ 4

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+ 5

+ 3

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Solution

The correct option is B $+ 5$ to $- 3$
Generally, when zinc reacts with nitric acid, it forms zinc nitrate. But when we take very dilute solution of nitric acid, if forms ammonium nitrate as well.

So, here Nitrogen is reducing from $+ 5$ to $- 3$ .

$4 Z n (s) + + 5 10 H N O_{3} (a q) ⟶ 4 Z n (N O_{3})_{2} (a q) + - 3 N H_{4} N O_{3} (a q) + 3 H_{2} O (l)$

Option B is correct.

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Suggest a list of the substances where carbon can exhibit oxidation states from –4 to +4 and nitrogen from –3 to +5.

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