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Electrochemical Series

When Zn metal...

Question

When Zn metal is added to $C u S O_{4}$ solution, Cu is precipitated. It is due to :

Oxidation of

C u^{+ 2}

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Reduction of

C u^{+ 2}

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Hydrolysis of

C u S O_{4}

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Ionization of

C u S O_{4}

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Solution

The correct option is B Reduction of $C u^{+ 2}$
Zn acts as a reducing agent and it reduces $C u^{2 +}$ to $C u$ and itself gets oxidised to $Z n^{2 +}$ .
The reaction is as follows:
$Z n + C u S O_{4} \to Z n S O_{4} + C u$

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