Whenever a hydrogen atom emits a photon in the Balmer series

It need not emit any more photon

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It may emit another photon in the Paschen series

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It must emit another photon in the Lyman series

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It may emit another photon on the Balmer series

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Solution

The correct option is B It must emit another photon in the Lyman series
Balmer series, electron is still in excited state. ( $n = 2$ ), so it will definitely come to a lower energy state by transit from ( $n = 2 t o n = 1$ )

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Whenever a hydrogen atom emits a photon in the Balmer series

The correct option is B It must emit another photon in the Lyman seriesBalmer series, electron is still in excited state. (n=2), so it will definitely come to a lower energy state by transit from (n=2ton=1)

The correct option is B It must emit another photon in the Lyman series
Balmer series, electron is still in excited state. ( $n = 2$ ), so it will definitely come to a lower energy state by transit from ( $n = 2 t o n = 1$ )