Question

Where is acceleration due to gravity maximum?

Answer 1

1. Gravitational acceleration at a height of $h$ above the surface ${\mathrm{g}}^{\mathrm{\prime }}=\mathrm{g}\left(1-\frac{2\mathrm{h}}{\mathrm{R}}\right)$ whereas $\mathrm{g}\text{'}$ is gravity maximum and $\mathrm{g}$ refers to gravitational force , $h$ refers to height.
2. This implies that when we rise higher above the earth's surface, our acceleration due to gravity diminishes.
3. We have$\mathrm{h}=0$ on the surface. Thus, $\mathrm{g}\prime =\mathrm{g}$ is the acceleration owing to gravity at the surface (maximum).
4. At the center of the earth, the acceleration due to gravity is also zero. As a result, gravity's acceleration is greatest at the earth's surface.